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An item was sold for Rs540 at a loss of 5%. what was it’s cost price​

By Emma

An item was sold for Rs540 at a loss of 5%. what was it’s cost price​

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Emma

The mean marks of 100 students were found to be 40 later it was discovered score of 53 was misread as 83 find the correct mean cor

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4(m + n) – 2(mn)

2 thoughts on “An item was sold for Rs540 at a loss of 5%. what was it’s cost price​”

  1. S.P= ₹ 540, loss%=5%

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.P

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 100

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 100

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP )

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP ) 1/20 = ( (CP – 540)/CP )

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP ) 1/20 = ( (CP – 540)/CP ) CP = 20 (CP – 540)

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP ) 1/20 = ( (CP – 540)/CP ) CP = 20 (CP – 540)20 = 20CP – 10800

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP ) 1/20 = ( (CP – 540)/CP ) CP = 20 (CP – 540)20 = 20CP – 1080020CP – CP = 10800

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP ) 1/20 = ( (CP – 540)/CP ) CP = 20 (CP – 540)20 = 20CP – 1080020CP – CP = 1080019CP = 10800

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP ) 1/20 = ( (CP – 540)/CP ) CP = 20 (CP – 540)20 = 20CP – 1080020CP – CP = 1080019CP = 10800CP = 10800/19

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP ) 1/20 = ( (CP – 540)/CP ) CP = 20 (CP – 540)20 = 20CP – 1080020CP – CP = 1080019CP = 10800CP = 10800/19CP =₹ 568.42

    S.P= ₹ 540, loss%=5%

    Let the Cost price = C.PLoss% =( loss/C.P) × 100Loss% =( (CP- SP)/CP ) × 1005 =( (CP – 540)/CP ) × 1005/100 = ( (CP – 540)/CP ) 1/20 = ( (CP – 540)/CP ) CP = 20 (CP – 540)20 = 20CP – 1080020CP – CP = 1080019CP = 10800CP = 10800/19CP =₹ 568.42

    Hence, the cost price of an item = ₹ 568.42

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  2. [tex]\underline\mathfrak\orange{Answer:—}[/tex]

    We have,

    SP = Rs 540

    Loss = 5%

    CP = ?

    .

    Therefore,

    [tex]SP = CP(1-\dfrac{loss\%}{100})[/tex]

    put the values in the above equation, we get

    [tex]\\\Rightarrow 540 = CP(1-\dfrac{5}{100})\\ \\ \Rightarrow540 = CP\times \dfrac{19}{20}[/tex]

    [tex]\Rightarrow CP = \dfrac{540 \times 20}{19} = Rs\ 568.42[/tex]

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