$\underbrace{{Question}{\mathrm{:}}\mathrm{{-}}}$
[tex]यदि \: x = 7 – 4 \sqrt{2} \: हो, तो \: (x + \frac{1}{x} ) \: का \:

2 thoughts on “$\underbrace{{Question}{\mathrm{:}}\mathrm{{-}}}$<br />[tex]यदि \: x = 7 – 4 \sqrt{2} \: हो, तो \: (x + \frac{1}{x} ) \: का \:”

1. Answer:

   put the value of x that is given 7-4√2

   Step-by-step explanation:

   x+1/x

   7-4√2+1/7-4√2

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2. Answer:

   14.

   Step-by-step explanation:

   Given that:

   [tex]x = 7 – 4 \sqrt{3} [/tex]

   To find:

   [tex]the \: value \: of \: (x + \frac{1}{x}) \\ [/tex]

   Solution:

   [tex]x + \frac{1}{x} = (7 – 4 \sqrt{3} ) + \frac{1}{7 – 4 \sqrt{3} } \\ [/tex]

   = $\frac{{\mathrm{(}}\mathrm{{-}}{4}\sqrt{3}{\mathrm{)}}^{2}\mathrm{{+}}{1}}{{7}\mathrm{{-}}{4}\sqrt{3}}$

   = $\frac{{\mathrm{49}}\mathrm{{-}}{\mathrm{56}}\sqrt{3}\mathrm{{+}}{\mathrm{48}}\mathrm{{+}}{1}}{{7}\mathrm{{-}}{4}\sqrt{3}}$

   = $\frac{{\mathrm{98}}\mathrm{{-}}{\mathrm{56}}\sqrt{3}}{{7}\mathrm{{-}}{4}\sqrt{3}}$

   = 14 Ans.

   [tex] {}^{i \: hope \: its \: help \: you.} [/tex]

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