The roots α,β of the quadratic equation x²-5x+2(k-5)=0 are such that α-β=3,find the value of k​

The roots α,β of the quadratic equation x²-5x+2(k-5)=0 are such that α-β=3,find the value of k​

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  1. Step-by-step explanation:

    Given x

    2

    −5x+3(k−1)=0 α,β are roots is given equation.

    α−β=11 __________ (1)

    using conditions we have α+β=5

    αβ=3(k−1)

    now α−β=

    α

    2

    2

    −2αβ

    =

    (α+β)

    2

    −4αβ

    (11)

    2

    =(α+β)

    2

    −4αβ

    121−25=−12(k−1)⇒

    12

    96

    =1−k

    [k=-7]

    Hence value of k is -7.

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