The roots α,β of the quadratic equation x²-5x+2(k-5)=0 are such that α-β=3,find the value of k About the author Isabelle
Step-by-step explanation: Given x 2 −5x+3(k−1)=0 α,β are roots is given equation. α−β=11 __________ (1) using conditions we have α+β=5 αβ=3(k−1) now α−β= α 2 +β 2 −2αβ = (α+β) 2 −4αβ (11) 2 =(α+β) 2 −4αβ 121−25=−12(k−1)⇒ 12 96 =1−k [k=-7] Hence value of k is -7. Reply
Step-by-step explanation:
Given x
2
−5x+3(k−1)=0 α,β are roots is given equation.
α−β=11 __________ (1)
using conditions we have α+β=5
αβ=3(k−1)
now α−β=
α
2
+β
2
−2αβ
=
(α+β)
2
−4αβ
(11)
2
=(α+β)
2
−4αβ
121−25=−12(k−1)⇒
12
96
=1−k
[k=-7]
Hence value of k is -7.