) एक मोटार ताशी काही वेगाने 240 किमी धावते. तिचा वेग ताशी 8 किमीने कमी केल्यास तिला तेवढेच अंतर जाण्यास पूर्वीपेक्षा 1 तास जास्त लागतो तर मोटारीचा मूळचा ताशी वेग काढा.10th chapter1
Given:–A motor runs 240 km at some speed per hour. If you reduce its speed by 8 km per hour, it takes 1 hour more to cover the same distance than before, then take the original speed of the car per hour. ?
Solution:–
Let us assume that, original speed of car is x km/h .
so,
→ T1 = D / S = (240/x) hours .
now,
→ New speed = (x – 8) hours .
→ T2 = 240/(x – 8) hours .
A/q,
→ 240/(x – 8) – 240/x = 1
→ 240[(x – x + 8]/(x² – 8x) = 1
→ x² – 8x = 240 * 8
→ x² – 8x – 1920 = 0
→ x² + 40x – 48x – 1920 = 0
→ x(x + 40) – 48(x + 40) = 0
→ (x + 40)(x – 48) = 0
→ x = (-40) or 48 .
since speed cant be in negative.
therefore, the original speed of the car is 48 km/h.
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Answer:
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Given :– A motor runs 240 km at some speed per hour. If you reduce its speed by 8 km per hour, it takes 1 hour more to cover the same distance than before, then take the original speed of the car per hour. ?
Solution :–
Let us assume that, original speed of car is x km/h .
so,
→ T1 = D / S = (240/x) hours .
now,
→ New speed = (x – 8) hours .
→ T2 = 240/(x – 8) hours .
A/q,
→ 240/(x – 8) – 240/x = 1
→ 240[(x – x + 8]/(x² – 8x) = 1
→ x² – 8x = 240 * 8
→ x² – 8x – 1920 = 0
→ x² + 40x – 48x – 1920 = 0
→ x(x + 40) – 48(x + 40) = 0
→ (x + 40)(x – 48) = 0
→ x = (-40) or 48 .
since speed cant be in negative.
therefore, the original speed of the car is 48 km/h.
Learn more :-
शांत जल में एक नाव को अपने गंतव्य स्थान तक पहुंचने और वहां
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