3. If n = 2 raise to 3 × 3 raise to 4 x 5 raise to 4 x7, then the number of consecutive zeros in n, where n is a
natura

2 thoughts on “<br />3. If n = 2 raise to 3 × 3 raise to 4 x 5 raise to 4 x7, then the number of consecutive zeros in n, where n is a<br />natura”

1. Answer:

   option b is the correct answer

   hope it’s correct

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2. Step-by-step explanation:

   n = 23 x 34 x 54 x 7

   n = 23 x 34 x 53 x 5 x 7

   n = (2 x 5)3 x 34 x 5 x 7

   n = (10)3 x 34 x 5 x 7

   n = 34 x 5 x 7 x 1000

   Thus, in the given natural number ‘n’ there are 3 zeros.

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