From a circular card sheet of radius 14cm, two circles of radius 3.5cm and 2 pointsa rectangle of length 3cm and breadth1cm are removed. (as shown in the adjoining figure).Find the areaof the remaining sheet. (Take Ti=22/7) * About the author Serenity
533cm² Step-by-step explanation: radius of circular card is 14cm area = 22/7*(14)² = 22/7*14*14 = 616cm² radius of circle is 3.5cm area = 22/7*(3.5)² = 22/7*3.5*3.5 = 38.5cm² two circles were removed = 2*38.5 = 77cm² breadth of rectangle is 1cm length of rectangle is 3cm area of rectangle = 3*1 = 3cm² two rectangles were removed = 2*3 = 6cm² Total area removed = 77+6 = 83cm² area of remaining sheet = 616-83 = 533cm² Reply
533cm²
Step-by-step explanation:
radius of circular card is 14cm
area = 22/7*(14)² = 22/7*14*14 = 616cm²
radius of circle is 3.5cm
area = 22/7*(3.5)² = 22/7*3.5*3.5 = 38.5cm²
two circles were removed = 2*38.5 = 77cm²
breadth of rectangle is 1cm
length of rectangle is 3cm
area of rectangle = 3*1 = 3cm²
two rectangles were removed = 2*3 = 6cm²
Total area removed = 77+6 = 83cm²
area of remaining sheet = 616-83 = 533cm²