A car running between two points P and Q on a straight path. If it travels half of distance between P and Q with velocity 40 km/h and other half with 60 km/h and return in the same manner. The average speed of the car is. explain strep by step About the author Alice
Step-by-step explanation: Avg Speed = Total distance/Total time Let the distance between P to Q is 2S It travels half of distance with 40km/h = S distance with 40km/hr Time Taken = distance/speed = S/40 hr and other half of distance with 60km/h = S distance with 60/hr Time Taken = S/60 hr Return with same manner = S distance with 40km/hr (=Time taken = S/40 hr) and other half of distance with 60km/h = S distance with 60/hr (=Time Taken = S/60 hr) Hence, total distance of the whole journey = 2S + 2S = 4S & Total time taken = S/40 + S/60 + S/40 + S/60 = (3S+2S+3S+2S)/120 hr = 10S/120 hr = 1S/12 hr Average Speed = 4S/(1S/12) km/hr = (4S×12)/1S km/hr = 48S/1S km/hr = 48 km/hr Reply
Step-by-step explanation:
Avg Speed = Total distance/Total time
Let the distance between P to Q is 2S
It travels half of distance with 40km/h
= S distance with 40km/hr
Time Taken = distance/speed
= S/40 hr
and other half of distance with 60km/h
= S distance with 60/hr
Time Taken = S/60 hr
Return with same manner
= S distance with 40km/hr (=Time taken = S/40 hr)
and other half of distance with 60km/h
= S distance with 60/hr (=Time Taken = S/60 hr)
Hence, total distance of the whole journey
= 2S + 2S
= 4S
& Total time taken
= S/40 + S/60 + S/40 + S/60
= (3S+2S+3S+2S)/120 hr
= 10S/120 hr
= 1S/12 hr
Average Speed = 4S/(1S/12) km/hr
= (4S×12)/1S km/hr
= 48S/1S km/hr
= 48 km/hr