solve the sum by elimination method 2x+3y=32 equation 1. 3x+4y=68 equation 2​

1 thought on “solve the sum by elimination method 2x+3y=32 equation 1. 3x+4y=68 equation 2​”

1. Answer:

   y= -40

   x= 76

   Step-by-step explanation:

   2x+3y=32

   3x+4y=68

   3(2x+3y=32)

   2(3x+4y=68)

   6x+9y=96

   6x+8y=136

   equation 1 – equation 2

   we get

   y= -40

   then substitute y value in equation

   we get

   x=76

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