3. Find the LCM and HCF of the following integers by applying the prime factorisationPImethod.(i) 12, 15 and 21 (ii) 17, 23 and 29(iii) 8, 9 and 25 About the author Nevaeh
LCM and HCF are 1) 12= 2×2×3 15=3×5 21=3×7 HCF=3 LCM= 2²×3×5×7 =2×2×3×5×7 =420 2) 17= 1×17 23= 1×23 29=1×29 HCF= 1 LCM=17×23×29 =11339 3) 8= 2×2×2 9=3×3 25=5×5 HCF=1 LCM= 1800 Reply
LCM and HCF are
1) 12= 2×2×3
15=3×5
21=3×7
HCF=3
LCM= 2²×3×5×7
=2×2×3×5×7
=420
2) 17= 1×17
23= 1×23
29=1×29
HCF= 1
LCM=17×23×29
=11339
3) 8= 2×2×2
9=3×3
25=5×5
HCF=1
LCM= 1800