◍ Here, the question has given us the simple interest, rate of interest and time that is Rs. 40, 5% per annum and for 1 year respectively. Now, the question has asked us to find the sum she has borrowed it means we have to find the principal. So to get the answer we simply have to apply the formula of SI by taking Principal as x and we will easily get our answer.
ANSWER:-
◈ The principal is Rs. 800.
GIVEN:-
☆ Simple Interest = Rs. 40
☆ Rate of Interest = 5% per annum
☆ Time = 1 year
TO FIND:-
↠Principal = ?
FORMULA:-
➾ Simple Interest = P × R × T / 100 [For finding theprincipal.]
SOLVING BY APPLYING THE FORMULA:-
☆ Simple Interest = Rs. 40
☆ Rate of Interest = 5% per annum
☆ Time = 1 year
➾ Simple Interest = P × R × T / 100
Finding theprincipal:–
Let the principal be x.
➢ 40 = x × 5 × 1 / 100
➢ 40 = x × 5 / 100
➢ Taking 100 to L.H.S.
➢ 40 × 100 = x × 5
➢ 4000 = x × 5
➢ 4000 = 5x
➢ 4000 / 5 = x
➢ 800 = x
➢ x = 800
Hence, we got the answer. The principal is of Rs. 800.
Solution:-
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◍ Here, the question has given us the simple interest, rate of interest and time that is Rs. 40, 5% per annum and for 1 year respectively. Now, the question has asked us to find the sum she has borrowed it means we have to find the principal. So to get the answer we simply have to apply the formula of SI by taking Principal as x and we will easily get our answer.
ANSWER:-
◈ The principal is Rs. 800.
GIVEN:-
☆ Simple Interest = Rs. 40
☆ Rate of Interest = 5% per annum
☆ Time = 1 year
TO FIND:-
↠Principal = ?
FORMULA:-
➾ Simple Interest = P × R × T / 100 [For finding the principal.]
SOLVING BY APPLYING THE FORMULA:-
☆ Simple Interest = Rs. 40
☆ Rate of Interest = 5% per annum
☆ Time = 1 year
➾ Simple Interest = P × R × T / 100
➢ 40 = x × 5 × 1 / 100
➢ 40 = x × 5 / 100
➢ Taking 100 to L.H.S.
➢ 40 × 100 = x × 5
➢ 4000 = x × 5
➢ 4000 = 5x
➢ 4000 / 5 = x
➢ 800 = x
➢ x = 800
Hence, we got the answer. The principal is of Rs. 800.
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