Find the distance between two parallel
lines 3x-4y-5=0 and 6x-8y+4=0.​

1 thought on “Find the distance between two parallel<br />lines 3x-4y-5=0 and 6x-8y+4=0.​”

1. Answer:

   Putting y=0 in 3x−4y+9=0, we get x=−3.

   Thus, (−3,0) is a point on the line 3x−4y+9=0.

   Length of the perpendicular from (−3,0) to 6x−8y−15=0 is given by

   d=62+(−8)2∣−3×6−8×0−15∣=1033

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