find the zeros of the quadratic polynomial x^2 – 4x – 32 and verify the relationship between the zeros and coefficient of the poly

1 thought on “find the zeros of the quadratic polynomial x^2 – 4x – 32 and verify the relationship between the zeros and coefficient of the poly”

1. Step-by-step explanation:

   Let f(x) = 4×2 ˗ 4x ˗ 3 = 4×2 ˗ (6x ˗ 2x) ˗ 3 = 4x^2 ˗ 6x + 2x ˗ 3 = 2x (2x ˗ 3) + 1(2x ˗ 3) = (2x + 1) (2x ˗ 3) To find the zeroes, set f(x) = 0 (2x + 1) (2x ˗ 3)= 0 2x + 1 = 0 or 2x ˗ 3 = 0 x = -1/2 or x = 3/2 Again, Sum of zeroes = (-1/2) + (3/2) = (-1+3)/2 = 2/2 = -b/a = (-Coefficient of x)/(Cofficient of x2) Product of zeroes = (-1/2)(3/2) = (-3)/4 = c/a = Constant term / Coefficient of x2Read more on Sarthaks.com – https://www.sarthaks.com/694814/find-zeros-quadratic-polynomials-3and-verify-relationship-between-zeros-coefficients

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