[tex]\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\orange{R }}}}}}}}}}}}}[/tex]… Given class mark :(xi) 47, 52,57,62,67,72,77 Class size (h) = Difference of two consecutive class marks = 52 – 47 = 5 Now, Class limits : (xi – h/2, xi +h/2) Class size (h) Difference of two consecutive class marks =52 – 47 = 5 Now , Class limits : (xi – h/2, xi + h/2) ( 47 – 5/2, 47 + 5/2) = ( 47-2.5 , 47 + 2.5) = ( 44.5 – 49.5 ) Therefore, 44.5 – 49.5 49.5 – 54.5 54.5 – 59.5 59.5 – 63.5 63.5 – 67.5 67.5 – 72.5 72.5 – 77.5 Step-by-step explanation: 100% correct answer Hope it’s helpful ✌️✌️ [tex]\huge\color{red}\boxed{\colorbox{black}{please\:mark\:me\: brilliance}}[/tex] [tex]\huge\underline\purple{\underline {Follow\:Me}}[/tex] Reply
[tex]\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\orange{R }}}}}}}}}}}}}[/tex]…
Given class mark :(xi)
47, 52,57,62,67,72,77
Class size (h)
= Difference of two
consecutive class marks
= 52 – 47
= 5
Now,
Class limits :
(xi – h/2, xi +h/2)
Class size (h)
Difference of two
consecutive class marks
=52 – 47
= 5
Now ,
Class limits :
(xi – h/2, xi + h/2)
( 47 – 5/2, 47 + 5/2)
= ( 47-2.5 , 47 + 2.5)
= ( 44.5 – 49.5 )
Therefore,
44.5 – 49.5
49.5 – 54.5
54.5 – 59.5
59.5 – 63.5
63.5 – 67.5
67.5 – 72.5
72.5 – 77.5
Step-by-step explanation:
100% correct answer
Hope it’s helpful ✌️✌️
[tex]\huge\color{red}\boxed{\colorbox{black}{please\:mark\:me\: brilliance}}[/tex]
[tex]\huge\underline\purple{\underline {Follow\:Me}}[/tex]