Answer: Given, foci c=8 and a= 6 we know, c²=a²+b² 64=36+b² b² = 28 equation of given hyperbola, y²/a² – x²/b² =1 y²/36 -x²/28 =1 7y² – 9x² = 252 Reply
Answer:
Given, foci c=8
and a= 6
we know, c²=a²+b²
64=36+b²
b² = 28
equation of given hyperbola, y²/a² – x²/b² =1
y²/36 -x²/28 =1
7y² – 9x² = 252