5. A, B and C together can complete apiece of work in 10 days. All the threestarted working at it together and after4 days ‘A’ left. Then B and C togethercompleted the work in 10 more days.‘A’ alone can complete the work in About the author Hailey
Answer: (a+b+c) do work in 10 days so,( a+b+c)’s work =1÷10 and as they work together for 4 days so work done by them in 4 days = 4÷10 =2÷5 remaining work = 1+2÷5 (b+c) take 10 more days to complete 3÷5 work so, (b+c)’s 1 day work =3÷5 now A’s 1 day work = 1÷10 – 3÷5 = 1÷25 A does 1÷25 work in 1 day therefore, A can complete 1 work in 25 day Reply
Answer:
(a+b+c) do work in 10 days
so,( a+b+c)’s work =1÷10 and as they work together for 4 days so work done by them in 4 days = 4÷10 =2÷5
remaining work = 1+2÷5
(b+c) take 10 more days to complete 3÷5 work
so, (b+c)’s 1 day work =3÷5
now A’s 1 day work = 1÷10 – 3÷5 = 1÷25
A does 1÷25 work in 1 day
therefore, A can complete 1 work in 25 day