Two paths each 2 m wide run across the middle of a
rectangular field. If the area of cross path is 196 m2 and its
length

2 thoughts on “Two paths each 2 m wide run across the middle of a<br />rectangular field. If the area of cross path is 196 m2 and its<br />length”

1. Answer:

   Two paths each 2 m wide run across the middle of a

   rectangular field. If the area of cross path is 196 m2 and its

   length is 60 m, find its breadth.

   (Ans: 40 m) step wise answer for long method

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2. Step-by-step explanation:

   Here,

   firstly note that, when these two paths cross each other

   a square is formed in the middle of side 2m, same as the width of the path.

   Area of that square= s²= (2m)²= 4m²

   Now while taking the length of these two path

   we must subtract the portion the square covers that’s= 2m from length and breadth

   in the first path

   w=2m

   length = 60m

   after deducting = 60m-2m= 58m

   The area of the first path= l×b=2m×58m=116m²

   Now on the second path

   w= 2m

   b= x

   after deducting = x-2m

   area= 2m(x-2m)

   according to the question, the area of these two path

   = 196m²

   But we know that the area of the square is also included

   Therefore,

   116m²+2m(x-2m)+4m²= 196m²

   120m²+2m(x)-4m²= 196m²

   2m(x)= 196m²-116m²

   x= 80m²/2m= 40m

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