Given Points →A(2,6) and B(4,8) →Trisect 2:1 , m = 2 and n = 1 We have →x₁ =2 , y₁ = 6 , x₂=4 and y₂ = 8 Formula [tex]\to\sf \bigg(\dfrac{mx_2+nx_1}{m+n} \bigg),\bigg(\dfrac{my_2+ny_1}{m+n} \bigg)[/tex] Put The Value on formula [tex]\to\sf\bigg(\dfrac{2\times4+1\times2}{2+1} \bigg),\bigg(\dfrac{2\times8+1\times6}{2+1}\bigg)[/tex] [tex]\to\sf\bigg(\dfrac{8+2}{3} \bigg),\bigg(\dfrac{16+6}{3}\bigg)[/tex] [tex]\sf\to \bigg(\dfrac{10}{3} ,\dfrac{22}{3} \bigg)[/tex] Answer [tex]\sf\to \bigg(\dfrac{10}{3} ,\dfrac{22}{3} \bigg)[/tex] Reply
Given Points
→A(2,6) and B(4,8)
→Trisect 2:1 , m = 2 and n = 1
We have
→x₁ =2 , y₁ = 6 , x₂=4 and y₂ = 8
Formula
[tex]\to\sf \bigg(\dfrac{mx_2+nx_1}{m+n} \bigg),\bigg(\dfrac{my_2+ny_1}{m+n} \bigg)[/tex]
Put The Value on formula
[tex]\to\sf\bigg(\dfrac{2\times4+1\times2}{2+1} \bigg),\bigg(\dfrac{2\times8+1\times6}{2+1}\bigg)[/tex]
[tex]\to\sf\bigg(\dfrac{8+2}{3} \bigg),\bigg(\dfrac{16+6}{3}\bigg)[/tex]
[tex]\sf\to \bigg(\dfrac{10}{3} ,\dfrac{22}{3} \bigg)[/tex]
Answer
[tex]\sf\to \bigg(\dfrac{10}{3} ,\dfrac{22}{3} \bigg)[/tex]