500 रुपयांवरील द.सा.द.शे. 10 टक्के चक्रवाढ व्याज दराने 2 वर्षाची रास व 3 वर्षाची रास यातील फरक किती
To find:
फरक किती
Solution:
The sum of money, P = Rs. 500
The rate of interest, R = 10% p.a.
Compound Interest for 2 years:
The no. of years, n = 2 years
[tex]A = P [1 + \frac{R}{100} ]^n[/tex]
[tex]\implies A = 500 [1 + \frac{10}{100} ]^2[/tex]
[tex]\implies A = 500 \times [\frac{110}{100} ]^2[/tex]
[tex]\implies A = 500 \times [1.1]^2[/tex]
[tex]\implies A = 605[/tex]
and
[tex]C.I. = A – P = 605 – 500 = 105[/tex]
Compound Interest for 3 years:
The no. of years, n = 3 years
[tex]A = P [1 + \frac{R}{100} ]^n[/tex]
[tex]\implies A = 500 [1 + \frac{10}{100} ]^3[/tex]
[tex]\implies A = 500 \times [\frac{110}{100} ]^3[/tex]
[tex]\implies A = 500 \times [1.1]^3[/tex]
[tex]\implies A = 665.50[/tex]
and
[tex]C.I. = A – P = 665.50 – 500 = 165.50[/tex]
Now,
The required difference is,
= C.I.₃ – C.I.₂
= Rs. 165.50 – Rs. 105
= Rs. 60.50
Thus, the difference between the compound interest for 2 years and 3 years at the rate of 10% on Rs.500 is → Rs. 60.50.
——————————————————————————————–
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Answer :–
we know that, when rate is compounded annually ,
Or,
Where,
putting values we get,
→ Difference = CI for 3 years – CI for 2 years .
→ D = 500[{1 + (10/100)}³ – 1] – 500[{1 + (10/100)}³ – 1]
→ D = 500[{1 + (1/10)}³ – 1] – 500[{1 + (1/10)}² – 1]
→ D = 500[(11/10)³ – 1] – 500[(11/10)² – 1]
→ D = 500[(1331 – 1000)/1000] – 500[(121 – 100)/100]
→ D = 500(331/1000) – 500(21/100)
→ D = (331/2) – 105
→ D = 165.5 – 105
→ D = Rs. 60.5 (Ans.)
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Given:
500 रुपयांवरील द.सा.द.शे. 10 टक्के चक्रवाढ व्याज दराने 2 वर्षाची रास व 3 वर्षाची रास यातील फरक किती
To find:
फरक किती
Solution:
The sum of money, P = Rs. 500
The rate of interest, R = 10% p.a.
Compound Interest for 2 years:
The no. of years, n = 2 years
[tex]A = P [1 + \frac{R}{100} ]^n[/tex]
[tex]\implies A = 500 [1 + \frac{10}{100} ]^2[/tex]
[tex]\implies A = 500 \times [\frac{110}{100} ]^2[/tex]
[tex]\implies A = 500 \times [1.1]^2[/tex]
[tex]\implies A = 605[/tex]
and
[tex]C.I. = A – P = 605 – 500 = 105[/tex]
Compound Interest for 3 years:
The no. of years, n = 3 years
[tex]A = P [1 + \frac{R}{100} ]^n[/tex]
[tex]\implies A = 500 [1 + \frac{10}{100} ]^3[/tex]
[tex]\implies A = 500 \times [\frac{110}{100} ]^3[/tex]
[tex]\implies A = 500 \times [1.1]^3[/tex]
[tex]\implies A = 665.50[/tex]
and
[tex]C.I. = A – P = 665.50 – 500 = 165.50[/tex]
Now,
The required difference is,
= C.I.₃ – C.I.₂
= Rs. 165.50 – Rs. 105
= Rs. 60.50
Thus, the difference between the compound interest for 2 years and 3 years at the rate of 10% on Rs.500 is → Rs. 60.50.
——————————————————————————————–
Also View:
Find the difference between CI and SI on RS 5000 for 1 year at 2% PA if the interest is compounDED half-yearly
brainly.in/question/13304173
Find the difference between the simple interest and compound interest on Rs. 16000 for 3/2 years at 5% per annum, compound interest being reckoned half-yearly.
brainly.in/question/895898
What will be the compound interest on *5,000, if it is compounded half-yearly for 1 year 6 months at 8% per annum?
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