Level-2
The age of a father is 25 years more than his son’s age. The product of their ages is 84 in years. What will
be

1 thought on “Level-2<br />The age of a father is 25 years more than his son’s age. The product of their ages is 84 in years. What will<br />be”

1. age of son =X

   age of father =X+25

   product of age= 84

   X(X+25)=84

   X^2+25X=84

   X^2+25X-84=0

   solving this we get ,X=3

   .: age of son in year =3

   age of father in year =X+25

   =3+25

   =28

   :. age of son after 10 years =3+10=13

   age of father after 10 years=38

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