Find the perimeter of Rectangles Whose sides are :
7 cm and 5 cm
11 cm and 14 cm
17 cm and 33 cm​​

2 thoughts on “Find the perimeter of Rectangles Whose sides are :<br />7 cm and 5 cm<br />11 cm and 14 cm<br />17 cm and 33 cm​​”

1. [tex] \huge \mathscr \pink \star\underline {Answer } \red \star[/tex]

   [tex] {\orange{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}[/tex]

   7 cm and 5 cm,11 cm and 14 cm,17 cm and 33 cm

   [tex]{\blue{\bigstar}} \ {\underline{\pink{\textsf{\textbf{To Find :-}}}}}[/tex]

   Perimeter of Rectangle.

   [tex]{\red{\bigstar}} \ {\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}[/tex]

   2(l+b)

   ______________________________________________________

   ❍7 cm and 5 cm

   We know that,

   Perimeter of Rectangle = 2(l+b)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 2(7+5)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 24 cm

   [tex]{\underline{\textsf{Hence,Perimeter \ of \ rectangle \ is {\textbf{25 cm}}}}} [/tex]

   [tex] \fbox \red{ Hence,Perimeter \ of \ rectangle \ is \ 24 cm }[/tex]

   ______________________________________________________

   ❍11 cm and 14 cm

   We know that,

   Perimeter of Rectangle = 2(l+b)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 2(11+14)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 50 cm

   [tex]{\underline{\textsf{Hence,Perimeter \ of \ rectangle \ is {\textbf{50 cm}}}}} [/tex]

   [tex] \fbox \pink{ Hence,Perimeter \ of \ rectangle \ is \ 50 cm }[/tex]

   ______________________________________________________

   ❍17 cm and 33 cm

   We know that,

   Perimeter of Rectangle = 2(l+b)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 2(17+33)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 100 cm

   [tex]{\underline{\textsf{Hence,Perimeter \ of \ rectangle \ is {\textbf{100 cm}}}}}[/tex]

   [tex] \fbox \green{ Hence,Perimeter \ of \ rectangle \ is \ 100 cm }[/tex]

   Reply

2. Given : 7 cm and 5 cm,11 cm and 14 cm,17 cm and 33 cm.

   To Find : Perimeter of Rectangle.

   Formula Used : 2(l+b)

   ⠀⠀⠀⠀⠀___________________________

   ❍7 cm and 5 cm

   We know that,

   Perimeter of Rectangle = 2(l+b)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 2(7+5)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 24 cm

   [tex]{\underline{\textsf{Hence,Perimeter \ of \ rectangle \ is {\textbf{24 cm}}}}}[/tex].

   [tex]\\[/tex]

   ❍11 cm and 14 cm

   We know that,

   Perimeter of Rectangle = 2(l+b)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 2(11+14)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 50 cm

   [tex]{\underline{\textsf{Hence,Perimeter \ of \ rectangle \ is {\textbf{50 cm}}}}}[/tex].

   [tex]\\[/tex]

   ❍17 cm and 33 cm

   We know that,

   Perimeter of Rectangle = 2(l+b)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 2(17+33)

   ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 100 cm

   [tex]{\underline{\textsf{Hence,Perimeter \ of \ rectangle \ is {\textbf{100 cm}}}}}[/tex].

   [tex]\\[/tex]

   More to know :

   Some Related Formulae :

   Perimeter of Square = 4 × (side)

   Perimeter of Rectangle = 2(l + b)

   Perimeter of Circle = 2πr

   Perimeter of Trapezoid = a + b + c + d

   Perimeter of Triangle = a + b + c

   Perimeter of Parallelogram = 2(a + b)

   Reply