Find a point on x-axis which is equidistant from (–3, 4) and (7, 6). answer needed urgently, thanks :]

Question

Charlie · Answer

Answer:   What point on the X-axis is equidistant from (7, 6) and (-3, 4) ? ⇒20x=60⇒x=3. ∴ the required point is P(3, 0). Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Caroline

if
[tex]x \: = \frac{1}{2} ( \sqrt{ \frac{a}{b} } – \sqrt{ \frac{b}{a} } )[/tex]
then show that,
[tex] \frac{2a

22. Rationalise the denominator of each of the following. 3\√3+√5-√2.

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