The volume and curved surface area of a cone are same. If the product of radius and height of the cone is 36 cm, then the slant height of the cone is: About the author Isabella
Given :- Volume and CSA of cone is same Product of radius and height = 36 To find :- Slant height Solution :- Let [tex]\mid \pmb {Radius = r}\mid[/tex] [tex]\mid \pmb{Height = h}\mid[/tex] [tex]\mid \pmb{Slant \; height = l}\mid[/tex] [tex]\sf Volume \; of \; cone = CSA\; of \; cone[/tex] [tex]\sf \dfrac{1}{3} \pi r^2h = \pi rl[/tex] [tex]\sf \pi r^2 h = \pi rl \times 3[/tex] [tex]\sf r h = 3l[/tex] [tex]\sf 36 = 3l[/tex] [tex]\sf l = \dfrac{36}{3}[/tex] l = 12 cm Reply
Answer: The slant height of the cone is 12 cm. Step-by-step explanation: Given that: The volume and curved surface area of a cone are same. The product of radius and height of the cone is 36 cm. To Find: The slant height of the cone. Finding the slant height of the cone: Volume of a cone = Curved surface area of a cone ⟶ (πr²h)/3 = πrl ⟶ πr²h = 3πrl Cancelling π and r both sides. ⟶ rh = 3l ⟶ 36 = 3l [Given] ⟶ l = 36/3 ⟶ l = 12 ∴ The slant height of the cone = 12 cm Reply
Given :-
Volume and CSA of cone is same
Product of radius and height = 36
To find :-
Slant height
Solution :-
Let
[tex]\mid \pmb {Radius = r}\mid[/tex]
[tex]\mid \pmb{Height = h}\mid[/tex]
[tex]\mid \pmb{Slant \; height = l}\mid[/tex]
[tex]\sf Volume \; of \; cone = CSA\; of \; cone[/tex]
[tex]\sf \dfrac{1}{3} \pi r^2h = \pi rl[/tex]
[tex]\sf \pi r^2 h = \pi rl \times 3[/tex]
[tex]\sf r h = 3l[/tex]
[tex]\sf 36 = 3l[/tex]
[tex]\sf l = \dfrac{36}{3}[/tex]
l = 12 cm
Answer:
Step-by-step explanation:
Given that:
To Find:
Finding the slant height of the cone:
Volume of a cone = Curved surface area of a cone
⟶ (πr²h)/3 = πrl
⟶ πr²h = 3πrl
Cancelling π and r both sides.
⟶ rh = 3l
⟶ 36 = 3l [Given]
⟶ l = 36/3
⟶ l = 12
∴ The slant height of the cone = 12 cm