The area of a rectangular plot is increased by 30% and its width remain as it was before. What will be the ratio between the area

The area of a rectangular plot is increased by 30% and its width remain as it was before. What will be the ratio between the area of new rectangle and the original rectangle?
1. 13:10
2: 10:13
3. 7:3
4. 3:7​

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2 thoughts on “The area of a rectangular plot is increased by 30% and its width remain as it was before. What will be the ratio between the area”

  1. Answer :-

    • Ratio = 13 : 10 [option A]

    Given :-

    • Area of rectangular plot increased by 30%

    To find :-

    • Ratio between new and original rectangle

    Explanation :-

    Let the Original rectangle’s area = y

    New rectangle area = (100 + increased percentage) of original rectangle

    [tex]\longmapsto\rm \bigg(100 + 30\bigg) \times y[/tex]

    [tex]\longmapsto\rm \dfrac{100 + 30}{100} \times y[/tex]

    [tex]\longmapsto\rm \dfrac{130}{100}\times y[/tex]

    [tex]\longmapsto\bf \dfrac{13}{10}y[/tex]

    Finding ratio,

    [tex]\longmapsto\rm \dfrac{13}{10}y = y[/tex]

    [tex]\longmapsto\rm 13y = 10\times y[/tex]

    [tex]\longmapsto\rm 13y = 10y[/tex]

    [tex] \red {\underline {\boxed{ \bf \longmapsto 13 =10 }}}[/tex]

    Hence, the ratio between new rectangle and the original rectangle = 13 : 10 [Option A].

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  2. Answer:

    If the area of a rectangular plot increase by 30% while its breadth remains same what will be the ratio of the areas of new and old figures ?

    Explanation

    Let original length = x and original breadth = y. ∴ Required ratio = (13xy10xy)=1310 = 13 : 10.

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