The area of a rectangular plot is increased by 30% and its width remain as it was before. What will be the ratio between the area of new rectangle and the original rectangle?1. 13:102: 10:133. 7:34. 3:7 About the author Maria
Answer :- Ratio = 13 : 10 [option A] Given :- Area of rectangular plot increased by 30% To find :- Ratio between new and original rectangle Explanation :- Let the Original rectangle’s area = y New rectangle area = (100 + increased percentage) of original rectangle [tex]\longmapsto\rm \bigg(100 + 30\bigg) \times y[/tex] [tex]\longmapsto\rm \dfrac{100 + 30}{100} \times y[/tex] [tex]\longmapsto\rm \dfrac{130}{100}\times y[/tex] [tex]\longmapsto\bf \dfrac{13}{10}y[/tex] Finding ratio, [tex]\longmapsto\rm \dfrac{13}{10}y = y[/tex] [tex]\longmapsto\rm 13y = 10\times y[/tex] [tex]\longmapsto\rm 13y = 10y[/tex] [tex] \red {\underline {\boxed{ \bf \longmapsto 13 =10 }}}[/tex] Hence, the ratio between new rectangle and the original rectangle = 13 : 10 [Option A]. Reply
Answer: If the area of a rectangular plot increase by 30% while its breadth remains same what will be the ratio of the areas of new and old figures ? Explanation Let original length = x and original breadth = y. ∴ Required ratio = (13xy10xy)=1310 = 13 : 10. is it useful Reply
Answer :-
Given :-
To find :-
Explanation :-
Let the Original rectangle’s area = y
New rectangle area = (100 + increased percentage) of original rectangle
[tex]\longmapsto\rm \bigg(100 + 30\bigg) \times y[/tex]
[tex]\longmapsto\rm \dfrac{100 + 30}{100} \times y[/tex]
[tex]\longmapsto\rm \dfrac{130}{100}\times y[/tex]
[tex]\longmapsto\bf \dfrac{13}{10}y[/tex]
Finding ratio,
[tex]\longmapsto\rm \dfrac{13}{10}y = y[/tex]
[tex]\longmapsto\rm 13y = 10\times y[/tex]
[tex]\longmapsto\rm 13y = 10y[/tex]
[tex] \red {\underline {\boxed{ \bf \longmapsto 13 =10 }}}[/tex]
Hence, the ratio between new rectangle and the original rectangle = 13 : 10 [Option A].
Answer:
If the area of a rectangular plot increase by 30% while its breadth remains same what will be the ratio of the areas of new and old figures ?
Explanation
Let original length = x and original breadth = y. ∴ Required ratio = (13xy10xy)=1310 = 13 : 10.
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