The area of a trapezium is 126cm. The height of the trapezium is 7cm. If one of the bases is longer than the other by 6cm, find the length of the bases About the author Evelyn
[tex]\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}[/tex] Answer: Length of bases are 15 cm and 21 cm. Step-by-step explanation: To find :- Length of bases. Solution :- Given that, Area of trapezium is 126 cm². Height of trapezium is 7 cm. Let, Other base be x cm. And One base be x + 6 cm. If the height 7 cm have two bases and height is of trapezium then the x and x + 6 are parallel sides of trapezium. We know, Area of trapezium = (a + b)/2 × h Put area, height and bases (parallel sides) of trapezium in formula : ⟶ 126 = (x + x + 6)/2 × 7 ⟶ 126 × 2 = 2x + 6 × 7 ⟶ 252 = 2x + 6 × 7 ⟶ 252/7 = 2x + 6 ⟶ 36 = 2x + 6 ⟶ 36 – 6 = 2x ⟶ 30 = 2x ⟶ 30/2 = x ⟶ x = 15 Length of bases :- One base = x + 6 = 15 + 6 = 21 cm Other base = x = 15 cm Reply
Answer: 28 Step-by-step explanation: Area= 1/2 h(a+b) 200= 1/2 ×8×(a+a+6) 200=4(2a+6) 50=2a+6 44=2a a=22 cm Longer side a+6=28 cm hope this helps you…. Reply
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Answer:
Length of bases are 15 cm and 21 cm.
Step-by-step explanation:
To find :-
Length of bases.
Solution :-
Given that,
Area of trapezium is 126 cm².
Height of trapezium is 7 cm.
Let, Other base be x cm.
And One base be x + 6 cm.
If the height 7 cm have two bases and height is of trapezium then the x and x + 6 are parallel sides of trapezium.
We know,
Area of trapezium = (a + b)/2 × h
Put area, height and bases (parallel sides) of trapezium in formula :
⟶ 126 = (x + x + 6)/2 × 7
⟶ 126 × 2 = 2x + 6 × 7
⟶ 252 = 2x + 6 × 7
⟶ 252/7 = 2x + 6
⟶ 36 = 2x + 6
⟶ 36 – 6 = 2x
⟶ 30 = 2x
⟶ 30/2 = x
⟶ x = 15
Length of bases :-
One base = x + 6 = 15 + 6 = 21 cm
Other base = x = 15 cm
Answer:
28
Step-by-step explanation:
Area= 1/2 h(a+b)
200= 1/2 ×8×(a+a+6)
200=4(2a+6)
50=2a+6
44=2a
a=22 cm
Longer side a+6=28 cm
hope this helps you….