A sack contains 40 apples and 60 mangoes out of which 50% of both apples and mangoes are sour. Two fruits are taken out of the sac

2 thoughts on “A sack contains 40 apples and 60 mangoes out of which 50% of both apples and mangoes are sour. Two fruits are taken out of the sac”

1. Answer:

   50% pf both the apple and mango are sour so probability of sour mango is 50%

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2. Answer:

   pls mark me as brainliest if you are satisfied

   Step-by-step explanation:

   Total no of mangoes = 20

   Total no of oranges = 30

   Out of total, 50% of each fruit is sour.

   2 fruits are picked at random.

   Let us assume:

   P(A) = probability of getting oranges

   P(B) = probability of getting sour fruit

   P(A∩B) = probability of getting sour oranges

   P(A) = 〖30〗_(C_2 )/〖50〗_(C_2 )

   = ((30 ×29 ×28!)/(2 ×28!))/((50 ×49 ×48!)/(2 ×48!))

   = (30 ×29)/(50 ×49) = 870/(50 ×49)

   P(B) = 〖25〗_(C_2 )/〖50〗_(C_2 )

   = ((25 ×24 ×23!)/(2 ×23!))/((50 ×49 ×48!)/(2 ×48!))

   = (25 ×24)/(50 ×49)

   = 600/(50 ×49)

   P(A∩B) = 〖15〗_(C_2 )/〖50〗_(C_2 )

   = ((15 ×14 ×13!)/(2 ×13!))/((50 ×49 ×48!)/(2 ×48!))

   = 210/(50 ×49)

   Prababilty of getting either oranges or either both are sour

   = P(A) + P(B)- P(A∩B) (removing sour oranges probability as it has been added twice)

   = 870/(50 ×49)+ 600/(50 ×49) – 210/(50 ×49)

   = (870+600-210)/(50 ×49) = 1260/2450

   = 126/245

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