1 thought on “Determine the magnitude of the resultant force and its direction, measured clockwise from the positive x axis.”
Answer:
pls mark me as brainliest if you are satisfied
Step-by-step explanation:
What you seek are the two-dimensional polar coordinates of a vector. Such coordinates are (magnitude, angle) symbolically (r, θ). They can be derived by converting the Cartesian two-dimensional coordinates (x, y) or (ai, bj) using Pythagorean theorem and simple trionometry.
For example, if the (x, y) vector = (3, -4), then the magnitude = sqrt(9+16) = sqrt(25) = 5. The angle = arctan(-4/3) = -53.13 degrees = -0.927 radians relative to unit vector (1, 0) — the positive x axis.
Answer:
pls mark me as brainliest if you are satisfied
Step-by-step explanation:
What you seek are the two-dimensional polar coordinates of a vector. Such coordinates are (magnitude, angle) symbolically (r, θ). They can be derived by converting the Cartesian two-dimensional coordinates (x, y) or (ai, bj) using Pythagorean theorem and simple trionometry.
For example, if the (x, y) vector = (3, -4), then the magnitude = sqrt(9+16) = sqrt(25) = 5. The angle = arctan(-4/3) = -53.13 degrees = -0.927 radians relative to unit vector (1, 0) — the positive x axis.
The polar coordinates are (5, -0.927).