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if abc are interior angles of triangle abc then show that sin B+C/2=cos A/2​

By Ayla

if abc are interior angles of triangle abc then show that sin B+C/2=cos A/2​

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Ayla

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2 thoughts on “if abc are interior angles of triangle abc then show that sin B+C/2=cos A/2​”

  1. Sin[(B+C)/2]

    • [Since A+B+C=180 for interior angles of triangle ABC.]

    then B+C=180-A.

    NOW Sin [(180-A)/2]

    =Sin[90-(A/2)]

    • since Sin(90-A)=CosA

    =Cos(A/2)

    Reply

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