Answer: demand (an amount) as a price for a service rendered or goods supplied. “wedding planners may charge an hourly fee of up to £150” Step-by-step explanation: pls mark brainliest Reply
What is the value of “a” and “b” if (5+2√3)/(7+4√3)=a+b√3? Sachidanand Das Answered 2 years ago Answer: a=11, b=-6 Solution: Given (5 + 2√3)/(7 + 4√3) = a + b√3 Rationalizing the denominator on left-hand-side by multiplying the numerator and denominator with (7 – 4√3), (5 + 2√3) (7 – 4√3)/(7 + 4√3) (7 – 4√3) = a + b√3 Multiply term by term the two expressions on numerator of L.H.S. and for the denominator apply the identity (m+n) (m-n) = m² – n² . We obtain, (35 – 20√3 + 14√3 – 8.√3.√3)/[7² – (4√3)²] = a + b√3 Or, (35 – 6√3 – 8.3)/(49 – 48) = a + b√3 Or, (35 – 6√3 – 24)/1 = a + b√3 Or, 11 – 6√3 = a + b√3 Now equate the rational and irrational terms from both sides. 11 = a Or, a = 11 – 6√3 = b√3 ⇒ b = -6 Verification: To prove (5 + 2√3)/(7 + 4√3) = a + b√3 i.e. to prove (5 + 2√3) = (a + b√3) (7 + 4√3) Substituting for a=11 and b=-6, R.H.S.= (a + b√3) (7 + 4√3) = (11 – 6√3) (7 + 4√3) = 11.7 + 11.4√3 – 6√3.7 – 6.4.√3.√3 = 77 + 44√3 – 42√3 – 24.3 = 77 + 2√3 – 72 = 5 + 2√3 = L.H.S. Reply
Answer:
demand (an amount) as a price for a service rendered or goods supplied.
“wedding planners may charge an hourly fee of up to £150”
Step-by-step explanation:
pls mark brainliest
What is the value of “a” and “b” if (5+2√3)/(7+4√3)=a+b√3?
Sachidanand Das
Answered 2 years ago
Answer: a=11, b=-6
Solution:
Given (5 + 2√3)/(7 + 4√3) = a + b√3
Rationalizing the denominator on left-hand-side by multiplying the numerator and denominator with (7 – 4√3),
(5 + 2√3) (7 – 4√3)/(7 + 4√3) (7 – 4√3) = a + b√3
Multiply term by term the two expressions on numerator of L.H.S. and for the denominator apply the identity (m+n) (m-n) = m² – n² . We obtain,
(35 – 20√3 + 14√3 – 8.√3.√3)/[7² – (4√3)²] = a + b√3
Or, (35 – 6√3 – 8.3)/(49 – 48) = a + b√3
Or, (35 – 6√3 – 24)/1 = a + b√3
Or, 11 – 6√3 = a + b√3
Now equate the rational and irrational terms from both sides.
11 = a
Or, a = 11
– 6√3 = b√3
⇒ b = -6
Verification:
To prove (5 + 2√3)/(7 + 4√3) = a + b√3
i.e. to prove (5 + 2√3) = (a + b√3) (7 + 4√3)
Substituting for a=11 and b=-6,
R.H.S.= (a + b√3) (7 + 4√3)
= (11 – 6√3) (7 + 4√3) = 11.7 + 11.4√3 – 6√3.7 – 6.4.√3.√3 = 77 + 44√3 – 42√3 – 24.3
= 77 + 2√3 – 72 = 5 + 2√3 = L.H.S.