(iv) In what ratio does the Y-axis divide the line segmentjoining the points P( – 4, 5) and Q(3. – 7)? About the author Eliza
Answer: Let the required ratio be k : 1. Then, the coordinates of the point of division are, (3k – 4/k + 1 , 7k + 5/k + 1) But, it is a point on y-axis on which x-coordinate of every point is zero. Therefore 3k – 4/ k + 1 = 0 3k – 4 = 0 k = 4/3 Thus, the required ratio is k = 4/3 or 4 : 3. Reply
Answer:
Let the required ratio be k : 1. Then, the coordinates of the point of division are,
(3k – 4/k + 1 , 7k + 5/k + 1)
But, it is a point on y-axis on which x-coordinate of every point is zero.
Therefore 3k – 4/ k + 1 = 0
3k – 4 = 0
k = 4/3
Thus, the required ratio is k = 4/3 or 4 : 3.