If f(x)=5×3+4×2−13x−25f(x)=5×3+4×2−13x−25 and f(x−3)=5×3−41×2+98x+kf(x−3)=5×3−41×2+98x+k , then k=​

1 thought on “If f(x)=5×3+4×2−13x−25f(x)=5×3+4×2−13x−25 and f(x−3)=5×3−41×2+98x+kf(x−3)=5×3−41×2+98x+k , then k=​”

1. Answer:

   K = -229

   Step-by-step explanation:

   f(x)= 5×3+4×2−13x−25 → (1)

   f(x−3)=5×3−41×2+98x+k → (2)

   # apply x = 0 in (1)

   so,

   f(0) = 5×3+4×2−13(0)−25

   f(0) = 15 + 8 – 0 – 25

   f(0) = 23- 25

   f(0) = -2 → (3)

   # apply x = 3 in (2)

   so,

   f(3-3) = 5×3−41×2+98(3)+k

   f(0) = 15 – 82 + 294 + k

   f(0) = 227 + k →(4)

   # compare (3) and (4)

   so,

   227 + k = -2

   k = -2 -227

   k = -229

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