The denominator of a rational number is greater than its numerator by 3. If numerator and denominator are increased by 1 and 4, respectively, the number obtained is Find the rational number. (4 1 2 1
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Answer:
Correct Question :-
The denominator of a rational number is greater than its numerator by 3. If numerator and denominator are increased by 1 and 4 respectively. The number obtained is ½. Find the rational number.
Given :-
The denominator of a rational number is greater than its numerator by 3. If numerator and denominator are increased by 1 and 4 respectively. The number obtained is ½.
To Find :-
What is the rational number.
Solution :-
Let, the numerator be x
And, the denominator will be x + 3
Then, the rational number is [tex]\sf \dfrac{x}{x + 3}[/tex]
Answer:
Correct Question :-
The denominator of a rational number is greater than its numerator by 3. If numerator and denominator are increased by 1 and 4 respectively. The number obtained is ½. Find the rational number.
Given :-
The denominator of a rational number is greater than its numerator by 3. If numerator and denominator are increased by 1 and 4 respectively. The number obtained is ½.
To Find :-
What is the rational number.
Solution :-
Let, the numerator be x
And, the denominator will be x + 3
Then, the rational number is [tex]\sf \dfrac{x}{x + 3}[/tex]
According to the question,
↦ [tex]\sf \dfrac{x + 1}{x + 3 + 4} =\: \dfrac{1}{2}[/tex]
↦ [tex]\sf \dfrac{x + 1}{x + 7} =\: \dfrac{1}{2}[/tex]
By doing cross multiplication we get,
↦ [tex]\sf 2(x + 1) =\: 1(x + 7)[/tex]
↦ [tex]\sf 2x + 2 =\: x + 7[/tex]
↦ [tex]\sf 2x – x =\: 7 – 2[/tex]
➠ [tex]\sf\bold{\green{x =\: 5}}[/tex]
Hence, the required rational number is :-
➲ [tex]\sf \dfrac{x}{x + 3}[/tex]
⇒ [tex]\sf \dfrac{5}{5 + 3}[/tex]
➦ [tex]\sf\bold{\purple{\dfrac{5}{8}}}[/tex]
[tex]\therefore[/tex] The rational number is [tex]\sf\boxed{\bold{\red{\dfrac{5}{8}}}}[/tex].