the distance between point A(4,6) and s(14,10) is
A. √116 units
B. 116 units
C. 2√30 units
D. 3√20 units​

2 thoughts on “the distance between point A(4,6) and s(14,10) is<br />A. √116 units<br />B. 116 units<br />C. 2√30 units<br />D. 3√20 units​”

1. Answer:

   the points are A( 4,6) and S( 14,10)

   using distance formula

   AS =

   [tex] \sqrt{ {(10 – 6)}^{?} + {(14 – 4)}^{2} } \\ = \sqrt{ {4}^{2} + {10}^{2} } \\ = \sqrt{16 + 100} \\ = \sqrt{116} [/tex]

   so ,the distance is √116 units.

   Step-by-step explanation:

   distance formula –

   √(y2 – y1)² + (X2 -x1)²

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2. Option A

   Step-by-step explanation:

   distance between point A nd S is √(4-14) ^2+ (6-10)^2

   viz √100+16 = √116

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