in how many years does the sum of 1200 became 1800 at the rate of simple intrest of 5% per annum​

2 thoughts on “in how many years does the sum of 1200 became 1800 at the rate of simple intrest of 5% per annum​”

1. Answer:

   [tex]\large{\underline{\underline{\sf {\pmb{\maltese{{Given}}}}}}} [/tex]

   • ➠ Amount = 1800
   • ➠ Principle = 1200
   • ➠ Rate = 5% per annum

   [tex]\large{\underline{\underline{\sf {\pmb{\maltese{{To \: Find}}}}}}} [/tex]

   • ➠ Time

   [tex]\large{\underline{\underline{\sf {\pmb{\maltese{{Using \: Formulae}}}}}}} [/tex]

   [tex]\circ \underline{\boxed {\sf \purple{S.I = Amount-Principal}}}[/tex]

   [tex] \circ\underline{ \boxed{\sf \purple{Time = \dfrac{S.I \times 100}{P \times R} }}}[/tex]

   [tex]\large{\underline{\underline{\sf {\pmb{\maltese{{Solution}}}}}}}[/tex]

   [tex]{\bf \pink\clubsuit \: \underline\frak { \pmb{ Firstly,finding \: the \: Simple \: Interest }}}[/tex]

   [tex] : \implies{\sf{S.I = Amount-Principal}}[/tex]

   • ➛ Substituting the values

   [tex] : \implies{\sf{S.I =1800-1200}}[/tex]

   [tex] : \implies{\sf{S.I =600}}[/tex]

   [tex] \bigstar{\underline {\boxed{\bf \red{S.I =600}}}}[/tex]

   • ★ Hence,The Simple Interest is 600.

   [tex]{\bf \pink\clubsuit \: \underline\frak{ \pmb{Now,Finding \: the \: Time }}}[/tex]

   [tex]{ : \implies\sf{Time = \dfrac{S.I \times 100}{P \times R} }}[/tex]

   • ➛ Substituting the values

   [tex]{ : \implies\sf{Time = \dfrac{600 \times 100}{1200 \times 5} }}[/tex]

   [tex]{ : \implies\sf{Time = \dfrac{60000}{6000} }}[/tex]

   [tex]{ : \implies\sf{Time = \cancel\dfrac{60000}{6000} }}[/tex]

   [tex]{ : \implies\sf{Time = 10 \: years}}[/tex]

   [tex] \bigstar\underline{\boxed{\bf \red{Time = 10 \: years}}}[/tex]

   • ★ Henceforth,The Time is 10 years.

   [tex]\large{\underline{\underline{\sf {\pmb{\maltese{{Know \: more}}}}}}} [/tex]

   ★ Formula of Simple Interest (S.I)

   [tex]: \implies\sf \purple{S.I = \dfrac{P \times R \times T}{100}}[/tex]

   ★ Formula of Principle(P) if Amount and Interest given

   • [tex]: \implies\sf \purple{P=Amount – Interest}[/tex]

   ★ Formula of Principle (P) if Interest,time and rate given

   • [tex]: \implies\sf \purple{P = \dfrac{Interest \times 100 }{Time \times Rate}}[/tex]

   ★ Formula of Principle (P) if amount,time and rate given

   • [tex]: \implies\sf \purple{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}}[/tex]

   ★ Formula of Amount if Principle (P) and Interest (I) given

   • [tex]{: \implies \sf \purple{Amount = Principle + Interest }}[/tex]

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2. [tex]❥\huge\red{\underline{{\bf A}}}\huge\orange{\underline{{\bf n}}}\huge\green{\underline{{\bf s}}}\huge\blue{\underline{{\bf w}}}\huge\purple{\underline{{\bf e}}}\huge\pink{\underline{{\bf r}}}[/tex]

   5 × 12 = 60 %

   100 + 60 = 160 % = Rs 1 800 FV

   PV 100 % = [100 ÷ 160] × Rs 1 800

   = Rs 1 125

   SI = FV – PV

   =1 800 – 1 125

   = Rs 675

   Proof: I = Prt = 1 125 × 12% × 5 yrs

   =Rs 675

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