A rare whale fossil was uncovered under layers of sediment. When the excavator took measurements, she found the tail to be as long

By Lyla

A rare whale fossil was uncovered under layers of sediment. When the excavator took measurements, she found the tail to be as long as its head plus a quarter of the length of the body. When the archaeologist came in, he measured the length of the body. He found it to be ¾ of the total length. They made arguments about how such a fish would swim in the water. To make proper predictions they measured the head size, and found it to be 4 inches long. What is the total length of this whale?​

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1 thought on “A rare whale fossil was uncovered under layers of sediment. When the excavator took measurements, she found the tail to be as long”

  1. Answer:

    Answer:

    Answer:

    [tex]\huge \bold \blue{Answer࿐}[/tex]

    Width of rectangle is 25 cm.

    Step-by-step explanation:

    Given :-

    A wire bend in form of square of side 30 cm.

    Then wire is again bend in form of rectangle of length 35 cm.

    To find :-

    Width of the rectangle.

    Solution :-

    Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and rectangular shape.

    So,

    Perimeter of square = 4 × side

    ⟶ Perimeter = 4 × 30

    ⟶ Perimeter = 120

    Thus,

    Perimeter of square is 120 cm.

    According to concept, Perimeter of square and perimeter of rectangle are equal.

    So, Perimeter of rectangle is 120 cm.

    Let, Breadth or width or rectangle be x cm.

    We know,

    Perimeter of rectangle = 2(Length + Breadth)

    ⟶ 120 = 2×(35 + x)

    ⟶ 120 = 70 + 2x

    \⟶ 120 – 70 = 2x

    ⟶ 50 = 2x

    ⟶ 50/2 = x

    ⟶ x = 25

    We take, Width of rectangle be x.

    Therefore,

    Width of rectangle is 25 cm.

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