An elevator descends into a mine shaft at the rate of 5 meters per minute. What will be its position after one hour?

2 thoughts on “An elevator descends into a mine shaft at the rate of 5 meters per minute. What will be its position after one hour?”

1. Answer:

   Answer. after 1hour=5×60=300. It’s position will be=15-300=-285=285m below the ground.

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2. Answer:

   after 1hour=5×60=300. It’s position will be=15-300=-285=285m below the ground.

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