if ( n-1 ) is a factor of 4n³+3n²–4n+k. then find the value of k.

Question

if ( n-1 ) is a factor of 4n³+3n²–4n+k. then find the value of k.​

Vivian · Answer

4n³ + 3n² - 4n + k    12n² + 6n - 4

Adalyn · Answer

G  i  v  e  n :     4n³ + 3n² - 4n + k      F  i  n  d :     Value of K      S  o  l  u  t  i  o  n :                   ▢  (n - 1) = n =  1                           ↬    4 ༝ (1)³ + 3 ༝ (1)² - 4 ༝ 1 + k          ↬  4 + 3 - 4 + k          ↬  3 + k          ↬  k = -3        H  e  n  c  e  ,     t  h  e     v  a  l  u  e     o  f     k     i  s      -    3   .

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