[tex]\small\fbox\red{Answer!}[/tex] Sum of three consecutive number = 102 So let the second number = a so, the first number = (a-1) then, third number will be = (a+1) So according to question, (a-1) + a + (a+1) = 102 a – 1 + a + a + 1 = 102 3a = 102 a = 102/3 a = 34 so the second number =34. [tex]{\huge{\overbrace{\underbrace{\orange{Fol.low\:\:Me}}}}}[/tex] Reply
Middle number is 0 you understand
[tex]\small\fbox\red{Answer!}[/tex]
Sum of three consecutive number = 102
So let the second number = a
so, the first number = (a-1)
then, third number will be = (a+1)
So according to question,
(a-1) + a + (a+1) = 102
a – 1 + a + a + 1 = 102
3a = 102
a = 102/3
a = 34
so the second number =34.
[tex]{\huge{\overbrace{\underbrace{\orange{Fol.low\:\:Me}}}}}[/tex]