Here, we are given a question from the topic Algebraic Expressions. We are given that the length of the rectangle is (3x + 10) units and breadth of the rectangle is (5x + 7) units. We have to find the perimeter of rectangle.
We’ll basically use here the formula of perimeter of rectangle to find the perimeter of the rectangle. By using the formula, we’ll perform the multiplication and addition of polynomials.
Step-by-step explanation:
perimeter of Rectangle= 2( length+ breadth)
=2(3 x +10 + 5x + 7)
=2(8x + 17)
=16x + 34
[tex] {\underline {\boxed {\large {\bf \gray { Perimeter = (16x + 34) \: units } }}}} [/tex]
Clarification :
Here, we are given a question from the topic Algebraic Expressions. We are given that the length of the rectangle is (3x + 10) units and breadth of the rectangle is (5x + 7) units. We have to find the perimeter of rectangle.
We’ll basically use here the formula of perimeter of rectangle to find the perimeter of the rectangle. By using the formula, we’ll perform the multiplication and addition of polynomials.
Explication of steps :
Given,
• Length of the rectangle = (3x + 10) units
• Breadth of the rectangle = (5x + 7) units
To calculate,
• Perimeter of the rectangle.
Calculation,
As we know that,
[tex]\bigstar \: \boxed{\sf { {Perimeter}_{(Rectangle)} = 2 ( \ell + b)}} \\ [/tex]
Substituting values,
[tex] \longrightarrow [/tex] Perimeter = 2 [ ( 3x + 10 ) + ( 5x + 7 ) ] units
[tex] \longrightarrow [/tex] Perimeter = 2 (3x + 10 + 5x + 7) units
[tex] \longrightarrow [/tex] Perimeter = 2 (3x + 5x + 10 + 7) units
[tex] \longrightarrow [/tex] Perimeter = 2 (8x + 17) units
[tex] \longrightarrow [/tex] Perimeter = 2(8x) + 2(17) units
[tex] \longrightarrow [/tex] Perimeter = 16x + 34 units
[tex] \underline{\boxed{\sf{ Perimeter_{(Rectangle)} = (16x + 34) \: units }}} \: \red{\bigstar}[/tex]
Therefore, perimeter of the rectangle is (16x + 34) units.
A little further…!
More about rectangles :