find the zero of the quadratic polynomial and verify the relationship between zero and Coefficient first x square – 2 x minus About the author Isabella
Answer: f(x)=x 2 −2x−8 ⇒f(x)=x 2 −4x+2x−8 ⇒f(x)=x(x−4)+2(x−4)] ⇒f(x)=(x−4)(x+2) Zeros of f(x) are given by f(x) = 0 ⇒x 2 −2x−8=0 ⇒(x−4)(x+2)=0 ⇒x=4 or x=−2 So, α=4 and β=−2 ∴ sum of zeros =α+β=4−2=2 Also, sum of zeros = Coefficient of x 2 Coefficient of x = 1 −(−2) =2 So, sum of zeros =α+β=− Coefficient ofx 2 Coefficient of x Now, product of zeros =αβ=(4)(−2)=−8 Also, product of zeros = Coefficient ofx 2 Constant term = 1 −8 =−8 ∴ Product of zeros = Coefficient of x 2 Constant term =αβ Reply
Answer: The quadratic polynomial is:x square-2x first,take x as common then we get x(x-2) first x=0 and second x=2 so two zeros of the given quadratic polynomial are 0 and 2. ans. we represent zeros of the quadratic polynomial by alpha and beta so to verify it use the following formula, alpha+ beta=-b/a and,alpha×beta=c/a. Hope it will help you Reply
Answer:
f(x)=x
2
−2x−8
⇒f(x)=x
2
−4x+2x−8
⇒f(x)=x(x−4)+2(x−4)]
⇒f(x)=(x−4)(x+2)
Zeros of f(x) are given by f(x) = 0
⇒x
2
−2x−8=0
⇒(x−4)(x+2)=0
⇒x=4 or x=−2
So, α=4 and β=−2
∴ sum of zeros =α+β=4−2=2
Also, sum of zeros =
Coefficient of x
2
Coefficient of x
=
1
−(−2)
=2
So, sum of zeros =α+β=−
Coefficient ofx
2
Coefficient of x
Now, product of zeros =αβ=(4)(−2)=−8
Also, product of zeros =
Coefficient ofx
2
Constant term
=
1
−8
=−8
∴ Product of zeros =
Coefficient of x
2
Constant term
=αβ
Answer:
The quadratic polynomial is:x square-2x
first,take x as common then we get x(x-2)
first x=0 and second x=2
so two zeros of the given quadratic polynomial
are 0 and 2. ans.
we represent zeros of the quadratic polynomial by alpha and beta so to verify it
use the following formula,
alpha+ beta=-b/a
and,alpha×beta=c/a.
Hope it will help you