A Garrison of 1200 men has provisions for 15 days. how long will the provisions last if the Garrison be increased by 600 men About the author Mia
Step-by-step explanation: 1200 men/600 men = 2 then, 15×2=30,, therefore, 30 days they can take for 600 mens,, Reply
[tex]\sf{✯Understanding\:the\:concept✯}[/tex] Here its given that garrison for 1200 men has provision for 15 days . and later, 600 men joined the garrison . and now we have to find the number of days that the provision will last after the joining of new 600 members. so here we can see that the number of days the provision will last is inversely proportional to the number of men. we can solve this problem by using the normal arithmetical method . [tex]\bf\pink{Let’s\:do\:it}[/tex] Total number of men after joining = 1200 + 600 =1800 so , For 1200 men = 15 days . For 1 men = 15×1200 days Therefore , [tex]\sf{For\:1800\:men= \frac{15 \times 1200}{1800} \: days}[/tex] Hence, the provision will last for 10 days Hope it helps u dear mate :) Reply
Step-by-step explanation:
1200 men/600 men = 2
then,
15×2=30,,
therefore, 30 days they can take for 600 mens,,
[tex]\sf{✯Understanding\:the\:concept✯}[/tex]
Here its given that garrison for 1200 men has provision for 15 days .
and later, 600 men joined the garrison .
and now we have to find the number of days that the provision will last after the joining of new 600 members.
so here we can see that the number of days the provision will last is inversely proportional to the number of men.
we can solve this problem by using the normal arithmetical method .
[tex]\bf\pink{Let’s\:do\:it}[/tex]
Total number of men after joining = 1200 + 600 =1800
so ,
For 1200 men = 15 days .
For 1 men = 15×1200 days
Therefore ,
[tex]\sf{For\:1800\:men= \frac{15 \times 1200}{1800} \: days}[/tex]
Hence, the provision will last for 10 days
Hope it helps u dear mate :)