Answer: Given to Factorise:– 4p² – 9q² Identity used:– [tex] {a}^{2} – {b}^{2} = (a + b)(a – b)[/tex] Solution:– 4p² – 9q² [tex] = ( {2p)}^{2} – {(3q)}^{2} [/tex] [tex] = (2p + 3q)(2p – 3q)[/tex] Reply
[tex]question[/tex] (2p) ² – (3q) ² It’s a formula of a² – b² = (a-b) (a+b) (2p – 3q) (2p – 3q) here’s your answer hope it helps Reply
Answer:
Given to Factorise:–
Identity used:–
[tex] {a}^{2} – {b}^{2} = (a + b)(a – b)[/tex]
Solution:–
4p² – 9q²
[tex] = ( {2p)}^{2} – {(3q)}^{2} [/tex]
[tex] = (2p + 3q)(2p – 3q)[/tex]
[tex]question[/tex]
(2p) ² – (3q) ²
It’s a formula of a² – b² = (a-b) (a+b)
(2p – 3q) (2p – 3q)
here’s your answer
hope it helps