*The price of one box is (a – 7) Rs. What is the total cost of (a + 7) boxes?* 1️⃣ ₹(a² – 14a + 49)2️⃣ ₹(a² – 49)3️⃣ ₹(a² + 14a + 49)4️⃣ ₹(a² + 49) About the author Skylar
Answer: Hope it helps!! Mark this answer as brainliest if u found it useful and follow me for quick and accurate answers… Step-by-step explanation: Given : Cost of one box = Rs. (a-7) To find : Cost of (a+7) boxes Solution : [tex]Cost_{(1 \: box)} = (a – 7) \\ \\ Total \: \: cost = cost_{(1 \: box)} \times (a + 7) \\ \\ Total \: \: cost = (a – 7)\times (a + 7) \\ \\ Cost_{(a + 7) \: boxes} = (a – 7)(a + 7) \\ \\ Using \: \: identity \: (x – y)(x + y) = x {}^{2} – {y}^{2} \\ \\ Total \: cost = (a) {}^{2} – (7) {}^{2} \\ \\ \bold\red{Total \: Cost =a {}^{2} – 49}[/tex] ∴ Total cost of (a+7) boxes is Rs. a²-49 Reply
Answer:
Hope it helps!! Mark this answer as brainliest if u found it useful and follow me for quick and accurate answers…
Step-by-step explanation:
Given : Cost of one box = Rs. (a-7)
To find : Cost of (a+7) boxes
Solution :
[tex]Cost_{(1 \: box)} = (a – 7) \\ \\ Total \: \: cost = cost_{(1 \: box)} \times (a + 7) \\ \\ Total \: \: cost = (a – 7)\times (a + 7) \\ \\ Cost_{(a + 7) \: boxes} = (a – 7)(a + 7) \\ \\ Using \: \: identity \: (x – y)(x + y) = x {}^{2} – {y}^{2} \\ \\ Total \: cost = (a) {}^{2} – (7) {}^{2} \\ \\ \bold\red{Total \: Cost =a {}^{2} – 49}[/tex]
∴ Total cost of (a+7) boxes is Rs. a²-49
Answer:
then the cost of (a+7) is a^2 – 49