Where will the hand of a clock stop if kavya starts from 5 and makes % of a rotation (2 )
anti-clock wise?​

2 thoughts on “Where will the hand of a clock stop if kavya starts from 5 and makes % of a rotation (2 )<br />anti-clock wise?​”

1. Answer:

   In one complete revolution the clock hand returns back to the same position. So, if it starts at 12 then it would again stop at 12, if it starts at 2 it would again stop at 2 and if it starts at 5 it would again stop at 5.

   Hope this helps..❤️

   Mark me as brainliest..❤️

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2. Answer:

   Step-by-step explanation:

   we know that

   1 rotation = 360° .

   so,

   → (3/4) of rotation = (3/4) * 360° = 270° .

   then,

   → 5 + 270° (anticlockwise)

   → 5 + {(180° + 90°)anticlockwise}

   → (5 + 180° anticlockwise) + 90° anticlockwise

   → 11 (opposite) + 90° anticlockwise

   → 11 + 90° anticlockwise

   → 11 + 3*30° anticlockwise

   → 11 – 3

   → 8 (Ans.)

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