Pipe A tokes 24 minute to fill a tank. Pipe B takes 32 minutes to fill the sametank. If both the pipes are opened simultaneously, after how much time shouldpipe A be closed so that it takes 16 minute to fill the tank. About the author Emma
Given • Two pipes can fill a tank in 24 min and 32 min respectively. To find • The time after which B should be closed so that the tank is full in 18 min. Approach and Working out From the question, it seems one pipe is A and another is B. So, pipe A will be open for complete 18 mins and Pipe B will be open for some time. Let, the capacity of the tank = LCM (24, 32) = 96 Units • So, capacity of pipe A = 96/24 = 4 units per min • Capacity of pipe B = 96 /32 = 3 units per mint Pipe A is open for 18 min. So, 18 * 4 = 72 units of tank will get filled. • Remaining (96-72) =24 units will be filled by pipe B. Time taken by pipe B to fill 24 units = 24/3 = 8 min. So, pipe B will be open for 8 mins. Reply
Given
• Two pipes can fill a tank in 24 min and 32 min respectively.
To find
• The time after which B should be closed so that the tank is full in 18 min.
Approach and Working out
From the question, it seems one pipe is A and another is B.
So, pipe A will be open for complete 18 mins and Pipe B will be open for some time.
Let, the capacity of the tank = LCM (24, 32) = 96 Units
• So, capacity of pipe A = 96/24 = 4 units per min
• Capacity of pipe B = 96 /32 = 3 units per mint
Pipe A is open for 18 min. So, 18 * 4 = 72 units of tank will get filled.
• Remaining (96-72) =24 units will be filled by pipe B.
Time taken by pipe B to fill 24 units = 24/3 = 8 min.
So, pipe B will be open for 8 mins.