ABCD rectangle with AB – 8 cm, BC = 16 cm and AE-4 cm. Find the area of ABCE. Ithe area of ABEC equal to the sum of the area of ABAE and ACDE. Why? About the author Ayla
Acc to the question, ABCD rectangle with AB=8cm, BC=16 cm and AE=4 cm. Area of ΔBCE = 1/2 x base x height = 1/2 x 16 x 8 = 64cm². Area of ΔABE = 1/2 x base x height = 1/2 x 4 x 8 = 16cm² Area of ΔCDE = 1/2 x base x height = 1/2 x (16-4) x 8 = 48cm² [tex] \huge \red {hope\:it\:helps} [/tex] Reply
Answer: Acc to the question, ABCD rectangle with AB=8cm, BC=16 cm and AE=4 cm. Area of ΔBCE = 1/2 x base x height = 1/2 x 16 x 8 = 64cm². Area of ΔABE = 1/2 x base x height = 1/2 x 4 x 8 = 16cm² Area of ΔCDE = 1/2 x base x height = 1/2 x (16-4) x 8 = 48cm² Reply
Acc to the question, ABCD rectangle with AB=8cm, BC=16 cm and AE=4 cm.
Area of ΔBCE = 1/2 x base x height = 1/2 x 16 x 8 = 64cm².
Area of ΔABE = 1/2 x base x height = 1/2 x 4 x 8 = 16cm²
Area of ΔCDE = 1/2 x base x height = 1/2 x (16-4) x 8 = 48cm²
[tex] \huge \red {hope\:it\:helps} [/tex]
Answer:
Acc to the question, ABCD rectangle with AB=8cm, BC=16 cm and AE=4 cm.
Area of ΔBCE = 1/2 x base x height = 1/2 x 16 x 8 = 64cm².
Area of ΔABE = 1/2 x base x height = 1/2 x 4 x 8 = 16cm²
Area of ΔCDE = 1/2 x base x height = 1/2 x (16-4) x 8 = 48cm²