Answer: No. Step-by-step explanation: Cancelling works only when multiplying and dividing. Your answer would be incorrect if you attempt to cancel during addition. Your question can be solved by taking LCM: [tex]\frac{-1}{5} + \frac{5}{2}\\= \frac{(-1 \times 2) + (5 \times 5)}{5 \times 2} \\[/tex] [tex]= \frac{(-2) + (25)}{10}\\= \frac{23}{10} \\= 2.3[/tex] If we tried cancelling: [tex]\frac{-1}{5} + \frac{5}{2}\\= \frac{-1}{1} + \frac{1}{2}\\= \frac{(-1 \times 2) + (1 \times 1)}{1 \times 2}\\= \frac{-2+1}{2}\\= \frac{-1}{2}\\= -0.5[/tex] This answer is clearly incorrect. Any corrections or suggestions for improvement are welcome 🙂 Reply
Answer:
No.
Step-by-step explanation:
Cancelling works only when multiplying and dividing. Your answer would be incorrect if you attempt to cancel during addition.
Your question can be solved by taking LCM:
[tex]\frac{-1}{5} + \frac{5}{2}\\= \frac{(-1 \times 2) + (5 \times 5)}{5 \times 2} \\[/tex]
[tex]= \frac{(-2) + (25)}{10}\\= \frac{23}{10} \\= 2.3[/tex]
If we tried cancelling:
[tex]\frac{-1}{5} + \frac{5}{2}\\= \frac{-1}{1} + \frac{1}{2}\\= \frac{(-1 \times 2) + (1 \times 1)}{1 \times 2}\\= \frac{-2+1}{2}\\= \frac{-1}{2}\\= -0.5[/tex]
This answer is clearly incorrect.
Any corrections or suggestions for improvement are welcome 🙂