Answer :- 25th term of the given A.P. is the first negative term. Solution :- [tex]\lonrightarrow[/tex][tex]\longrightarrow[/tex] The given A.P. is – 19, 18.2, 17.4 …. Here, The first term (a) = 19 The difference between two consecutive terms (d) = 18.2 – 19 = 17.4 – 18.2 = -0.8 [tex]\lonrightarrow[/tex][tex]\longrightarrow[/tex] Let the nth term term of the given A.P. be negative Then, [tex]T_n <0[/tex] [Using the formula, [tex]T_{n}= a +(n-1)d[/tex]] => [a + (n – 1)d] < 0 => [19 + (n – 1)-0.8] < 0 => [19 – 0.8 n + 0.8] < 0 => [19.8 – 0.8 n] < 0 => – 0.8 n < -19.8 => 0.8 n > 19.8 => n > [tex]\dfrac{19.8}{0.8}[/tex] => n > 24.75 => n > 25 [after round -off] Therefore, n = 25, i.e., 25th term is the first negative term. [tex]\star[/tex] Checking it – [tex]T_{24}[/tex] = 19 + (24 – 1)-0.8 = 19 + (23)-0.8 = 19 – 18.4 = 0.6 [tex]T_{25}[/tex] = 19 + (25 – 1)-0.8 = 19 + (24)-0.8 = 19 – 19.2 = -0.2 After checking our answer it is confirmed that 25th term is the first negative term of the A.P. 19, 18.2, 17.4. Reply
Answer :-
25th term of the given A.P. is the first negative term.
Solution :-
[tex]\lonrightarrow[/tex][tex]\longrightarrow[/tex] The given A.P. is – 19, 18.2, 17.4 ….
Here,
The first term (a) = 19
The difference between two consecutive terms (d) = 18.2 – 19 = 17.4 – 18.2 = -0.8
[tex]\lonrightarrow[/tex][tex]\longrightarrow[/tex] Let the nth term term of the given A.P. be negative
Then, [tex]T_n <0[/tex]
[Using the formula, [tex]T_{n}= a +(n-1)d[/tex]]
=> [a + (n – 1)d] < 0
=> [19 + (n – 1)-0.8] < 0
=> [19 – 0.8 n + 0.8] < 0
=> [19.8 – 0.8 n] < 0
=> – 0.8 n < -19.8
=> 0.8 n > 19.8
=> n > [tex]\dfrac{19.8}{0.8}[/tex]
=> n > 24.75
=> n > 25 [after round -off]
Therefore, n = 25, i.e., 25th term is the first negative term.
[tex]\star[/tex] Checking it –
[tex]T_{24}[/tex] = 19 + (24 – 1)-0.8 = 19 + (23)-0.8 = 19 – 18.4 = 0.6
[tex]T_{25}[/tex] = 19 + (25 – 1)-0.8 = 19 + (24)-0.8 = 19 – 19.2 = -0.2
After checking our answer it is confirmed that 25th term is the first negative term of the A.P. 19, 18.2, 17.4.