If the number 2345a 60b is exactly divisible by 3 and 5, then find the maximum value of a+b is​

If the number 2345a 60b is exactly divisible by 3 and 5, then find the maximum value of a+b is​

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Aubrey

2 thoughts on “If the number 2345a 60b is exactly divisible by 3 and 5, then find the maximum value of a+b is​”

  1. Answer:

    16

    Step-by-step explanation:

    We know,

    If the sum of digits of a number is divisible by 3 then the number is divisible by 3

    So,

    2+3+4+5+(7) = 21

    6+0+9 = 15

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