find the discriminate in each of the following quadratic equations. (1) √3x^2 – 2√2x – 2 √3=0 About the author Rylee
Solution: To find discriminant, we have formula: ⇒D =b²-4ac Here, D=Discriminant b=coefficient of x a=coefficient of x² c=Constant term By substituting all values: D=(-2√2)²-4(√3)(-2√3) D=8+24 D=32 Required value of D is 32. More:- When value of D is +ve then the quadratic equation will have two distinct roots. When value of D is -ve then the quadratic equation will have no real roots. When value of D is 0 then the quadratic equation will have two equal roots. Reply
Solution:
To find discriminant, we have formula:
⇒D =b²-4ac
Here,
By substituting all values:
D=(-2√2)²-4(√3)(-2√3)
D=8+24
D=32
Required value of D is 32.
More:-
Step-by-step explanation:
b^2-4ac
(-2√2)^2-4(√3)(-2√3)
(8)-4(√3)(-2√3)
8-4(-6)
8+24
32