1 thought on “3. For 10s, the velocity of a car that travels with a constant acceleration, changes from 10m/s to 30m/s. How far does the car tra”
Answer:
Step-by-step explanation:
Given,
Time Taken = 10s
For the specified time interval i.e. for 10 seconds the car moves with a constant velocity of 10 m/s and is displaced by 10 m/s x 10s = 100 m (Assuming the car is moving in a straight line.)
Therefore displacement at the end of 10 s = 100m
Therefore as a consequence of this uniform acceleration ( the acceleration does not vary with time i.e =2m/s²), the velocity will increase linearly with time given by the equation v= u+at
Answer:
Step-by-step explanation:
Given,
Time Taken = 10s
For the specified time interval i.e. for 10 seconds the car moves with a constant velocity of 10 m/s and is displaced by 10 m/s x 10s = 100 m (Assuming the car is moving in a straight line.)
Therefore displacement at the end of 10 s = 100m
Therefore as a consequence of this uniform acceleration ( the acceleration does not vary with time i.e =2m/s²), the velocity will increase linearly with time given by the equation v= u+at
the parameters are as follows :
u = initial velocity=10m/s
a = acceleration= 2m/s²